## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$v = 30~m/s$
We can see that this is the fourth harmonic since there are 4 antinodes. We can find the wavelength. $\lambda = \frac{2L}{n}$ $\lambda = \frac{(2)(0.60~m)}{4}$ $\lambda = 0.30~m$ We can find the wave speed as: $v = f~\lambda$ $v = (100~Hz)(0.30~m)$ $v = 30~m/s$