Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 21 - Superposition - Exercises and Problems - Page 621: 11


The mass of the sculpture is 12 kg

Work Step by Step

We can find the speed of the wave along the wire. $v = f~\lambda$ $v = (f)~(2L)$ $v = (80~Hz)(2)(0.90~m)$ $v = 144~m/s$ We can find the tension in the wire. $v = \sqrt{\frac{T}{\mu}}$ $v = \sqrt{\frac{T}{m/L}}$ $T = \frac{v^2~m}{L}$ $T = \frac{(144~m/s)^2(0.0050~kg)}{0.90~m}$ $T = 115.2~N$ The tension in the wire will be equal to the weight of the sculpture. We can find the mass of the sculpture. $mg = T$ $m = \frac{T}{g}$ $m = \frac{115.2~N}{9.80~m/s^2}$ $m = 12~kg$ The mass of the sculpture is 12 kg
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