Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 14 - Oscillations - Exercises and Problems - Page 404: 47


$f = 1.7~Hz$

Work Step by Step

When the spring is stretched a distance of $x = 9.0~cm$, the force from the spring is equal in magnitude to the weight. We can write an expression for $\frac{k}{m}$: $kx = mg$ $\frac{k}{m} = \frac{g}{x}$ We can find the frequency of the oscillations as: $f = \frac{1}{2\pi}~\sqrt{\frac{k}{m}}$ $f = \frac{1}{2\pi}~\sqrt{\frac{g}{x}}$ $f = \frac{1}{2\pi}~\sqrt{\frac{9.80~m/s^2}{0.090~m}}$ $f = 1.7~Hz$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.