# Chapter 12 - Rotation of a Rigid Body - Exercises and Problems - Page 350: 51

The speed of a point at the front edge of the wheel is 28 m/s

#### Work Step by Step

Since the wheel is rolling at 20 m/s, then every point on the wheel has a horizontal component of speed that is equal to 20 m/s and directed forward. If the wheel is rolling at 20 m/s, then every point on the edge of the wheel is rotating with a speed of 20 m/s. From this rotation, a point at the front edge of the wheel has a vertical component of speed that is 20 m/s directed straight down. A point at the front edge of the wheel has a horizontal component of speed equal to 20 m/s and a vertical component of speed equal to 20 m/s. We can find the speed of a point at the front edge of the wheel. $v = \sqrt{(v_x)^2+(v_y)^2}$ $v = \sqrt{(20~m/s)^2+(20~m/s)^2}$ $v = 28~m/s$ The speed of a point at the front edge of the wheel is 28 m/s.

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