Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 12 - Rotation of a Rigid Body - Exercises and Problems - Page 350: 45


The angular momentum is $2.1~kg~m^2/s$

Work Step by Step

We can express the angular velocity in units of rad/s; $\omega = (120~rpm)(\frac{2\pi~rad}{1~rev})(\frac{1~min}{60~s})$ $\omega = 4\pi~rad/s$ We can find the moment of inertia of the bar as; $I = \frac{1}{12}MR^2$ $I = \frac{1}{12}(0.50~kg)(2.0~m)^2$ $I = 0.167~kg~m^2$ We can find the angular momentum about the axle: $L = I~\omega$ $L = (0.167~kg~m^2)(4\pi~rad/s)$ $L = 2.1~kg~m^2/s$ The angular momentum is $2.1~kg~m^2/s$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.