Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 8 - Rotational Kinematics - Problems - Page 216: 64



Work Step by Step

The mandible's angular displacement is $$\theta=\Big(\frac{90^o}{360^o}\Big)\times(2\pi rad)=\frac{\pi}{2}rad$$ The time it takes is $t=1.3\times10^{-4}s$. The average angular velocity is $$\overline\omega=\frac{\theta}{t}=1.2\times10^4rad/s$$
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