Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Problems - Page 166: 26


a) $s=10m$ b) $t=3.64s$

Work Step by Step

a) When the snowmobile is moving, it is under the influence of 2 opposing forces: drive force $D$ and kinetic friction $f_k$. The snowmobile goes at a constant speed, so we know these 2 forces are equal: $D=f_k=205N$ When the drive force is shut off, $f_k$ acts as the only force influencing the skier's motion by stopping it. $f_k$ opposes the motion in the opposite direction of the displacement, so $$W=(f_k\cos180)s=-f_ks (1)$$ According to the work-energy theorem, $W=\frac{1}{2}mv_f^2-\frac{1}{2}mv_0^2$ Because $v_f=0$, we can rewrite $W=-\frac{1}{2}mv_0^2 (2)$ From (1) and (2), we have $$-f_ks=-\frac{1}{2}mv_0^2$$ $$s=\frac{mv_0^2}{2f_k}$$ We have $m=136kg$, $v_0=5.5m/s$ and $f_k=205N$ $$s=10m$$ b) We can use the equations of kinematics to find $t$. As $s=10m$, $v_0=5.5m/s$, $v_f=0$, we have $$s=\Big(\frac{v_f+v_0}{2}\Big)t$$ $$t=\frac{2s}{v_f+v_0}=3.64s$$
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