Answer
Work done = 3.2 $\times$ $10^{3}$ J
Work Step by Step
Work done = $\Delta$$E_{k}$
= 0.5m$v^{2}$ - 0.5m$u^{2}$
= 0.5(70.3)($11.3^{2}$) - 0.5(70.3)($6.10^{2}$)
$\approx$ 3.2 $\times$ $10^{3}$ J
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 6 - Work and Energy - Problems - Page 166: 17
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