Answer
2.5 $\times$ $10^{7}$ J
Work Step by Step
Work done by catapault
= total work done on jet - work done by thrust engine
= 4.5 $\times$ $10^{7}$ - 2.3 $\times$ $10^{5}$ $\times$ 87
$\approx$ 2.5 $\times$ $10^{7}$ J
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 6 - Work and Energy - Problems - Page 166: 13
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
