Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Problems - Page 165: 6


(a) $P=54.88N$ (b) $W=1056J$ (c) $W=-1056J$ (d) $W=0$

Work Step by Step

(a) The shopping cart has a constant horizontal velocity, so there is no acceleration, and that means the horizontal forces balance each other. If we call the pushing force $P$, its horizontal component will be $P\cos29^o$. Opposing this pushing force is friction $f$. We show above that these forces balance each other, so $$P\cos29=f=48N$$ $$P=\frac{48}{\cos29}=54.88N$$ (b) The component $P\cos29$ propels directly the movement of the cart for $s=22m$, so the work done is positive. $$W=(P\cos29)s=48\times22=1056J$$ (c) Force $f$ has the same magnitude as $P\cos29$ and exerts force on the cart for the same $s=22m$, but since $f$ opposes the motion, its work is negative. $$W=-1056J$$ (d) Gravitational force points downward, so it does not influence the horizontal movement of the cart. Its work is $W=0$
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