Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Problems - Page 165: 3



Work Step by Step

We have $F=3\times10^3N$ and $s=850m$ The force is applied to stop the truck, so $\vec{F}$ and $\vec{s}$ are in opposite direction, meaning $\theta=180^o$ The work done by $F$ is $$W=(F\cos180)s=-2.55\times10^6J$$ As we can see, the work is negative, because the force applied is opposite in direction from the displacement.
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