Answer
e) is correct.
Work Step by Step
The work done by force $\vec{F}$ on the box can be calculated by $$W=(F\cos\theta)s$$
In case A, the angle $\vec{F}$ makes with $\vec{v}$ is $\theta$ $(0\lt\theta\lt90^o)$, so $W_A=(F\cos\theta)s$
In case B, the angle $\vec{F}$ makes with $\vec{v}$ is $0$, so $W_B=(F\cos0)s=Fs$
In case C, the angle $\vec{F}$ makes with $\vec{v}$ is $90^o$, so $W_C=(F\cos90)s=0$
Obviously, $W_C$ is the smallest. Since $F\cos\theta\lt F\cos0$, $W_A\lt W_B$
To rank the work done in ascending order: C, A, B.
