Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 6 - Work and Energy - Focus On Concepts - Page 164: 2

Answer

b) is correct.

Work Step by Step

The work done by force $\vec{F}$ on the object can be calculated by $$W=(F\cos\theta)s$$ The angle $\theta$ $\vec{F}$ makes with the object's motion decides the sign of $W$. For $W\gt0$, $\theta$ should be in between $(0, 90^o)$. Here, we see that $\vec{F}$ can only make such angles with the $-x$ and $+y$ axis. Therefore, the work done by $\vec{F}$ can only be positive when the displacement of the object is along the $-x$ or $+y$ axis.
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