## Physics (10th Edition)

$v_2=1.33\times10^4m/s$
We take the planet's mass to be $M$. Satellite 1 has $v_1=1.7\times10^4m/s$ and $r_1=5.25\times10^6m$ Satellite 2 has $r_2=8.6\times10^6m$ From the formula to find orbital speed $v=\sqrt{\frac{GM}{r}}$, we have $$\frac{v_2}{v_1}=\sqrt{\frac{\frac{GM}{r_2}}{\frac{GM}{r_1}}}=\sqrt{\frac{r_1}{r_2}}=0.78$$ $$v_2=0.78v_1=1.33\times10^4m/s$$