Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 139: 26


The minimum distance is $170.73m$

Work Step by Step

The closest case scenario is that the woman makes her circular turn and finishes it right beside the seawall. In this case, the distance from the seawall that she begins making the turn equals the radius $r$ of her circular path. In other words, this exercise asks for this value of $r$. We have $v=26m/s$, $\theta=22^o$ and $g=9.8m/s^2$. We can find $r$ by $$\tan\theta=\frac{v^2}{rg}$$ $$r=\frac{v^2}{g\tan\theta}=170.73m$$
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