Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 5 - Dynamics of Uniform Circular Motion - Problems - Page 139: 24

Answer

(a) $v_{min}=19.32m/s$ (b) $v_{max}=23.45m/s$

Work Step by Step

1) Find $\tan\theta$ Take $d$ to be the difference between the largest and the smallest radius, we have $d=165-112=53m$ From the figure, we can see that $$\tan\theta=\frac{h}{d}=\frac{18}{53}=0.34$$ The formula for a banked curve is $$\tan\theta=\frac{v^2}{rg}$$ $$v=\sqrt{\tan\theta rg} (1) $$ (a) $v_{min}$ will correspond to $r_{min}=112m$. Apply equation (1): $$v_{min}=\sqrt{0.34\times112\times9.8}=19.32m/s$$ (b) $v_{max}$ will correspond to $r_{max}=165m$. Apply equation (1): $$v_{max}=\sqrt{0.34\times165\times9.8}=23.45m/s$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.