## Physics (10th Edition)

a) $F_{a}$ = 3.6 N b) $F_{b}$ = 0.4 N
$F_{net}$ = ma = 8 $\times$ 0.5 = 4 N $F_{a}$ + $F_{b}$ = 4 N $F_{net}$ = ma = 8 $\times$ 0.4 = 3.2 N $F_{a}$ - $F_{b}$ = 3.2 N $F_{a}$ - $F_{b}$ + 0.8 = $F_{a}$ + $F_{b}$ 2 $\times$ $F_{b}$= 0.8 $F_{b}$ = 0.4 N $F_{a}$ = 3.6 N