Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 4 - Forces and Newton's Laws of Motion - Problems - Page 113: 4


The average net force exerted on the car and riders by the magnets is equal to $3.5 \times 10^4N$.

Work Step by Step

1. Find the acceleration of the car and its riders. $v = v_0 + at$ ** They started at rest, so $v_0 = 0$ $v = at$ $45m/s = a \times (7.0s)$ Divide both sides by 7.0s: $\frac{45m/s}{7.0s} = a$ $a = 6.4 m/s^2$ 2. Calculate the net force exerted on the car and riders: $F=ma$ $F = (5.5\times10^3kg)(6.4m/s^2)$ $F = 3.5 \times 10^4 \frac{kg*m}{s^2} = 3.5 \times 10^4 N$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.