Answer
0.97 s
Work Step by Step
Please see the attached image first.
By using trigonometry we can get,
$tan18^{\circ}=\frac{V_{y}}{V_{x}}=\frac{V_{y}}{29\space m/s\times cos36^{\circ}}=>V_{y}=29\space m/s(0.81)(0.32)=7.52\space m/s$
Let's apply equation 3.3b $V=u+at$ in the vertical direction to find the flight time.
$\uparrow V=u+at$ ; Let's plug known values into this equation.
$7.52\space m/s=29\space m/s \times sin 36^{\circ}+(-9.8\space m/s^{2})t$
$t=0.97\space s$
