## Physics (10th Edition)

t = $\frac{distance}{speed}$ = $\frac{17}{41}$ $\approx$ 0.415 s $s_{v}$ = ut + 0.5a$t^{2}$ = 0 $\times$ 0.415 + 0.5 $\times$ 9.8 $\times (0.415)^2$ $\approx$ 0.844 m