Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 3 - Kinematics in Two Dimensions - Problems: 29

Answer

0.844 m

Work Step by Step

t = $\frac{distance}{speed}$ = $\frac{17}{41}$ $\approx$ 0.415 s $s_{v}$ = ut + 0.5a$t^{2}$ = 0 $\times$ 0.415 + 0.5 $\times$ 9.8 $\times (0.415)^2$ $\approx$ 0.844 m
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