Answer
3.4 m
Work Step by Step
Let's apply equation 3.5b $S=ut+\frac{1}{2}at^{2}$ in the vertical direction to find the traveled time of the criminal.
$\uparrow S=ut+\frac{1}{2}at^{2}$ ; Let's plug known values into this equation.
$-2\space m=0+\frac{1}{2}(-9.8\space m/s^{2})t^{2}$
$t=0.64\space s$
Let's apply the equation $S=ut$ in the horizontal direction to find the horizontal distance traveled after launch.
$\rightarrow S=ut$ ; Let's plug known values into this equation.
$D=5.3\space m/s\times 0.64\space s=3.4\space m$
Horizontal distance traveled after launch = 3.4 m