Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 18 - Electric Forces and Electric Fields - Problems - Page 509: 12


121.5 N

Work Step by Step

F= $ k\frac{|q_{1}q_{2}|}{r^{2}}$ Thus, we find: $ k\frac{|q_{1}q_{2}|}{r^{2}}$= 1.5 N When the distance is reduced to one-ninth of its original value, F= $ k\frac{|q_{1}q_{2}|}{(\frac{r}{9})^{2}}$= $ k\frac{|q_{1}q_{2}|}{r^{2}} \times 9^{2}$ =$ 1.5 N\times81$ = 121.5 N
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