Answer
$0\space J-Adiabatic\space proces $
Work Step by Step
Here we use equation 15.1 $Q=\Delta U+W$ to find the heat.
$Q=\Delta U+W$ ; Let's plug known values into this equation.
$Q=(228\space J+115\space J)+(-166\space J-177\space J)=0\space J$
Since the heat is zero, the overall process is adiabatic
