Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 15 - Thermodynamics - Problems - Page 415: 1

Answer

(a) $1.6\times10^{4}J$ (b) $-4.2\times10^{4}J$ (c) $-2.6\times10^{4}J$

Work Step by Step

(a) The work (W) = $1.6\times10^{4}J$ (b) The change in internal energy $(\Delta U)=-4.2\times10^{4}J$ (c) Let's apply the first law of thermodynamics, $$Q=\Delta U+W$$ Let's plug known values into this equation. $Q=-4.2\times10^{4}J+1.6\times10^{4}J=-2.6\times10^{4}J$
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