Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 15 - Thermodynamics - Problems - Page 415: 4

Answer

$+2.8\times10^{4}J$

Work Step by Step

Let's apply the first law of thermodynamics $Q=\Delta U+W$ to find the change in the internal energy of the system. $$Q=\Delta U+W=>\Delta U=Q-W$$ Let's plug known values into this equation. $$\Delta U=+7.6\times10^{4}J-(+4.8\times10^{4}J)=+2.8\times10^{4}J$$ The internal energy of the system increases (+ sign in $\Delta U$)
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