Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 14 - The Ideal Gas Law and Kinetic Theory - Problems - Page 386: 48

Answer

$3\times10^{-3}kg/m^{3}$

Work Step by Step

Here we use Fick's law $\frac{m}{t}=\frac{DA\Delta C}{L}$ to find the lower concentration. $\frac{m}{t}=\frac{DA\Delta C}{L}=\frac{DA(C_{2}-C_{1})}{L}$ $C_{1}=C_{2}-\frac{L(\frac{m}{t})}{DA}$ ; Let's plug known values into this equation. $C_{1}=8.3\times10^{-3}kg/m^{3}-\frac{(0.02\space m)(4.2\times10^{-14}kg/s)}{(1.06\times10^{-9}m^{2}/s)(1.5\times10^{-4}m^{2})}$ $C_{1}=3\times10^{-3}kg/m^{3}$
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