Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 10 - Simple Harmonic Motion and Elasticity - Problems - Page 277: 53

Answer

260 m

Work Step by Step

Recall that $\Delta P=-B\frac{\Delta V}{V_{0}}$ Bulk modulus for pyrex glass is $B=2.6\times10^{10}\,N/m^{2}$ Change in volume $\Delta V=-1.0\times10^{-10}\,m^{3}$ (negative sign for decrease) Original volume $V_{0}=(1.0\times10^{-2}\,m)^{3}=1.0\times10^{-6}\,m^{3}$ Change in pressure $\Delta P=-(2.6\times10^{10}\,N/m^{2})\times\frac{-1.0\times10^{-10}\,m^{3}}{1.0\times10^{-6}\,m^{3}}$ $=2.6\times10^{6}\,N/m^{2}$ For every $1\,m$ depth, there is an increase in pressure by $1.0\times10^{4}\, N/m^{2}$. Therefore, Required depth=$\frac{2.6\times10^{6}\,N/m^{2}}{(1.0\times10^{4}\,N/m^{2})/m}=260\,m$
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