Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 10 - Simple Harmonic Motion and Elasticity - Problems - Page 277: 46


The tower's height is $21m$.

Work Step by Step

In a simple pendulum, $$\frac{2\pi}{T}=\sqrt{\frac{g}{L}}$$ $$\frac{g}{L}=\frac{4\pi^2}{T^2}$$ $$L=\frac{gT^2}{4\pi^2}$$ The pendulum's period $T=9.2s$. The tower's height, therefore, is $$L=21m$$
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