Physics (10th Edition)

Published by Wiley
ISBN 10: 1118486897
ISBN 13: 978-1-11848-689-4

Chapter 10 - Simple Harmonic Motion and Elasticity - Problems: 9

Answer

0.240 m

Work Step by Step

s = ut + 0.5a$t^{2}$ 4 = 0 + 0.5a$(0.75)^{2}$ a = 14.2 m/$s^{2}$ Net force = ma = 7(14.2) = 99.6 N F = k$\Delta$x 415($\Delta$x) = 99.6 $\Delta$x $\approx$ 0.240 m
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