Answer
2.29 $\times 10^{-3}$ m
Work Step by Step
We first find:
F = $\frac{mv^{2}}{r}$ = k$\Delta$x
$\frac{m}{k}$ = $\frac{xr}{v^{2}}$
= $\frac{0.010(0.21)}{3^{2}}$
= 2.33 $\times$ $10^{-4}$
We now find the value of x:
F = mg = k$\Delta$x
$\frac{m}{k}$ = $\frac{x}{g}$
2.33 $\times$ $10^{-4}$ = $\frac{x}{9.8}$
x $\approx$ 2.29 $\times 10^{-3}$ m
