## Physics (10th Edition)

2.29 $\times 10^{-3}$ m
We first find: F = $\frac{mv^{2}}{r}$ = k$\Delta$x $\frac{m}{k}$ = $\frac{xr}{v^{2}}$ = $\frac{0.010(0.21)}{3^{2}}$ = 2.33 $\times$ $10^{-4}$ We now find the value of x: F = mg = k$\Delta$x $\frac{m}{k}$ = $\frac{x}{g}$ 2.33 $\times$ $10^{-4}$ = $\frac{x}{9.8}$ x $\approx$ 2.29 $\times 10^{-3}$ m