Answer
The motion's angular frequency is $6.04rad/s$
Work Step by Step
From Conceptual Example 2, we learn that when a spring is divided into two halves, each half's spring constant is twice that of the original spring.
Therefore, when the mentioned spring is cut into 4 shorter ones, each spring will have $k=420\times4=1680N/m$
An object of mass $m=46kg$ is attached to one spring. The motion's angular frequency is $$\omega=\sqrt{\frac{k}{m}}=6.04rad/s$$
