Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 207: 59b

$ v=19m/s $

Subscript: i = initial f= final a = air resistance $ mass = \frac{weight}{gravity}$ $mass = \frac{5.29}{9.8}$ $mass = 0.54$ $U_i = K_f + E_a$ $ K_f= U_i- E_a$ $ \frac{1}{2}mv^2= mgh - F_ah$ $ \frac{1}{2}mv^2= Wh- F_ah$ $ v=\sqrt { \frac{ 2(Wh- F_ah)}{m}} $ $ v=\sqrt { \frac{ 2[(5.29\times19.44)- (0.265\times19.44)]}{0.54}} $ $ v=19m/s $