Answer
The answer in part(a) increases
The answer in part(b) increase
Work Step by Step
PART $(a)$ SOLUTION:
$v_f^2 =2gd(sin\theta - μ_kcos\theta) $
$\frac{v_f^2 }{2g(sin\theta - μ_kcos\theta)}= d$
If $μ_k$ decreases because it's part of the denominator, the value of d increases.
PART $(a)$ SOLUTION:
$v_f^2 =2gd(sin\theta - μ_kcos\theta) $
If $μ_k$ decreases because it's part of the numerator, the value of v will increase
