Answer
2.05m/s^2
Work Step by Step
weight of first box = 2.9N
weight of second box = 6.9N
coefficient friction of first box = 0.089
coefficient friction of second box = 0.27
angle of plane = 24˚
Net force of first box is given by
$/F1sinθ - f1 - T/$
f = µF = 0.089F1cosθ
Net force of second box is given by
$/F2sinθ - f2 - T/$
f = µF = 0.27F2cosθ
therefore: equation
$/(m1+m2)a = F1sinθ+F2sinθ - f1 - f2/$
so
a = [ 2.9sin24˚+6.9sin24˚ - 0.089(2.9cos24˚) - 0.27(6.9cos24˚) ] ÷ (2.9/9.8 + 6.9/9.8)
a = 2.05 m/s^2
