Answer
$a = 2.3~m/s^2$
Work Step by Step
We can find the acceleration of the system of block A and block B:
$m_B~g-m_A~g~\mu_k = (m_A+m_B)~a$
$a = \frac{m_B~g-m_A~g~\mu_k}{m_A+m_B}$
$a = \frac{(22~N)-(44~N)~(0.15)}{(44~N/9.8~m/s^2)+(22~N/9.8~m/s^2)}$
$a = 2.3~m/s^2$
