Answer
$F=160N$
Work Step by Step
The force from kinetic friction is equal to $$F_{k}=\mu_kmg$$ Substituting known values of $\mu_k=0.80$, $m=20kg$, and $g=9.8m/s^2$ yields a force of $$F=(0.80)(20kg)(9.8m/s^2)$$ $$F=160N$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 6 - Force and Motion-II - Problems - Page 140: 8
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