Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 5 - Force and Motion-I - Problems - Page 118: 25b

Answer

$S=8.3\times10^4Km$

Work Step by Step

We can find the distance traveled in one day as, $t=24\times60\times60=86400s$ We know that $S=vt+\frac{1}{2}at^2$ As $v=0\frac{m}{s}$ so $S=\frac{1}{2}at^2$ We plug in the known values in the formula to obtain: $S=\frac{1}{2}(0.0222)^2(86400)^2$ $S=8.3\times 10^7m=8.3\times 10^4\times 10^3m=8.3\times10^4Km$
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