Answer
$a=3.67\frac{m}{s^2}$
Work Step by Step
We know that $a=\frac{F_{net}}{m}$...................eq(1)
But we also know that $m=\frac{W}{g}$
$m=\frac{820}{9.8}$
$m=83.7Kg$
We plugin the known values in eq(1) to obtain: $a=\frac{307}{83.7}$
$a=3.67\frac{m}{s^2}$
