Answer
$F_{net}=307N$
Work Step by Step
The magnitude of net force is given as
$F_{net}=\sqrt{F_x^2+F_y^2}$
We plugin the known values $F_x=285N$ and $F_y=-115N$ to obtain:
$F_{net}=\sqrt{(285)^2+(-115)^2}$
$F_{net}=307N$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 5 - Force and Motion-I - Problems - Page 118: 23c
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
