Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 43 - Energy from the Nucleus - Problems - Page 1330: 9c

Answer

$t = 2.6\times 10^4~years$

Work Step by Step

In part (b), we found that the amount of energy released is $8.2\times 10^{13}~J$ We can find the time that this energy could light a 100 W lamp: $t = \frac{8.2\times 10^{13}~J}{100~W}$ $t = 8.2\times 10^{11}~s$ $t = (8.2\times 10^{11}~s)[\frac{1~year}{(365)(24)(3600~s)}]$ $t = 2.6\times 10^4~years$
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