Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 43 - Energy from the Nucleus - Problems - Page 1330: 10

Answer

$$ 181 \mathrm{\ MeV} $$

Work Step by Step

The energy released is $$ \begin{array}{l}{Q=\left(m_{u}+m_{n}-m_{\mathrm{c}}-m_{\mathrm{Rb}}-2 m_{n}\right) c^{2}} \\ {\quad=(235.04392 \mathrm{u}-1.00867 \mathrm{u}-140.91963 \mathrm{u}-92.92157 \mathrm{u})(931.5 \mathrm{MeV} / \mathrm{u})} \\ {\quad=181 \mathrm{\ MeV}}\end{array} $$
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