Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 43 - Energy from the Nucleus - Problems - Page 1330: 1b

Answer

$$4.3 \times 10^{8} $$

Work Step by Step

Since $R \propto 1 / T_{1 / 2}(\text { see } \mathrm{Eq} .42-20),$ the ratio of rates is $$\frac{R_{\alpha}}{R_{\text {fision }}}=\frac{ {T_{1 / 2}}_{\text {fision }} } {{\mathrm{T}_{1 / 2}}_{\alpha} }=\frac{3.0 \times 10^{17} \mathrm{y}}{7.0 \times 10^{8} \mathrm{y}}=4.3 \times 10^{8} . $$
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