Answer
$E = 1.29 \times 10^{-2} J$
Work Step by Step
To find the energy, we need to first convert the dose into $Gy$ which is equivalent to $J/Kg$
$Dose = \frac{D}{RBE}$
$Dose = \frac{250 \times 10^{-6}}{0.85}$
$Dose = 2.94 \times 10^{-4} Gy$
Total energy received
$E = D \times RBE$
$ E = ( 2.94 \times 10^{-4} J/kg) (44kg) $
$E = 1.29 \times 10^{-2} J$
