Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1306: 66b

Answer

$R = 3.92 \times 10^{-9} Ci $

Work Step by Step

$1 \space Ci = 3.70\times 10^{10} Bq $ Taking from previous answer, $R =\frac{ 145 Bq}{ 3.70\times 10^{10} Bq/ Ci} $ $R = 3.92 \times 10^{-9} Ci $
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