Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1306: 61c

Answer

$N_{Uo} = 1.684 \times 10^{19}$

Work Step by Step

Before the uranium decays into lead, the original number is $N_{Uo} = N_U + N_{Pb} $ $N_{Uo} = 1.06 \times 10^{19} + 6.24 \times 10^{18}$ $N_{Uo} = 1.684 \times 10^{19}$
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