Answer
$\beta=1.1\times 10^{-6}$
Work Step by Step
To find the speed parameter, use the equation $$\beta=\frac{v}{c}$$ where c is the speed of light, $c=3.00\times 10^8m/s$. Velocity must be in meters per second, so dimensional analysis should be performed. $$\frac{1200km}{1hr}\times \frac{1hr}{60min}\times \frac{1min}{60s} \times \frac{1000m}{1km}$$ $$=330m/s$$ Substituting known values of $v=330m/s$ and $c=3.0\times 10^8m/s$ yields a speed parameter of $$\beta=\frac{330m/s}{3.0\times 10^8m/s}=1.1\times 10^{-6}$$
