Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1152: 102b


$2.2\times10^{-18}\ m$

Work Step by Step

We know that the time taken by the electron to travel a distance d is $t=6.72\times 10^{-10}\ s$. During this time, the electron falls a vertical distance. So, using kinematics formula; $y = ut+\frac{1}{2}at^2$ $y=0+\frac{1}{2}gt^2$ $y=0.5\times9.8\times(6.72\times 10^{-10}\ s)^2$ $y=2.2\times10^{-18}\ m$
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