## Fundamentals of Physics Extended (10th Edition)

$2.2\times10^{-18}\ m$
We know that the time taken by the electron to travel a distance d is $t=6.72\times 10^{-10}\ s$. During this time, the electron falls a vertical distance. So, using kinematics formula; $y = ut+\frac{1}{2}at^2$ $y=0+\frac{1}{2}gt^2$ $y=0.5\times9.8\times(6.72\times 10^{-10}\ s)^2$ $y=2.2\times10^{-18}\ m$