Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1152: 101a



Work Step by Step

We first convert KwH to J: $E=2.2\times 10^{12}KW.h=2.2\times 10^{12}\times 1000\times 3600$ $E=7.92\times 10^{18}J$ We know that: $E=mc^2$ $m=\frac{E}{c^2}$ We plug in the known values to obtain: $m=\frac{7.92\times 10^{18}}{(3\times 10^8)^2}=88kg$
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