## Fundamentals of Physics Extended (10th Edition)

$m=88kg$
We first convert KwH to J: $E=2.2\times 10^{12}KW.h=2.2\times 10^{12}\times 1000\times 3600$ $E=7.92\times 10^{18}J$ We know that: $E=mc^2$ $m=\frac{E}{c^2}$ We plug in the known values to obtain: $m=\frac{7.92\times 10^{18}}{(3\times 10^8)^2}=88kg$