Answer
$\lambda=6.28\times 10^{-6}m$
Work Step by Step
To find the wavelength of the wave, remember that a wave equation is in the form of $$y(x,t)=Asin(kx+\omega t)$$ where $k$ is the wave number. The wave number is defined as $$k=\frac{2\pi}{\lambda}$$ Solving for $\lambda$ leaves $$\lambda=\frac{2\pi}{k}$$ Using the value of $k=1.00\times 10^6 m^{-1}$ yields $$ \lambda=\frac{2\pi}{1.00\times 10^6 m^{-1}}=6.28\times 10^{-6}m$$
