Answer
The angle of incidence does not depend on the wavelength of the light.
Work Step by Step
We can use Equation (33-49) to find the Brewster angle $\theta_B$ at the interface between air $n_1$ and water $n_2$:
$\theta_B = tan^{-1}~\frac{n_2}{n_1}$
$\theta_B = tan^{-1}~\frac{1.33}{1.00}$
$\theta_B = 53.1^{\circ}$
At an angle of incidence of $~~53.1^{\circ}~~$ the light reflected from water will be completely polarized.
From the equation, we can see that the angle of incidence does not depend on the wavelength of the light.
